How do X_L and X_C vary with frequency, and what is the behavior of a series LC circuit as frequency changes?

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Multiple Choice

How do X_L and X_C vary with frequency, and what is the behavior of a series LC circuit as frequency changes?

Explanation:
In a series LC circuit, the two reactive parts respond opposite to frequency: the inductor’s reactance increases with frequency (X_L = ωL), while the capacitor’s reactance decreases with frequency (X_C = 1/(ωC)). The total reactance is X = X_L − X_C = ωL − 1/(ωC). At low frequencies, the capacitor dominates, so the circuit looks capacitive (negative reactance). At high frequencies, the inductor dominates, so it looks inductive (positive reactance). There is a particular frequency, ω0 = 1/√(LC), where the two reactive parts cancel each other out, so X ≈ 0 and the impedance is purely resistive (equal to the series resistance, or zero in an ideal lossless case). Thus, the impedance is smallest and purely resistive at resonance, and it grows large as you move away from that frequency, approaching infinity in the ideal case as ω → 0 or ω → ∞.

In a series LC circuit, the two reactive parts respond opposite to frequency: the inductor’s reactance increases with frequency (X_L = ωL), while the capacitor’s reactance decreases with frequency (X_C = 1/(ωC)). The total reactance is X = X_L − X_C = ωL − 1/(ωC).

At low frequencies, the capacitor dominates, so the circuit looks capacitive (negative reactance). At high frequencies, the inductor dominates, so it looks inductive (positive reactance). There is a particular frequency, ω0 = 1/√(LC), where the two reactive parts cancel each other out, so X ≈ 0 and the impedance is purely resistive (equal to the series resistance, or zero in an ideal lossless case).

Thus, the impedance is smallest and purely resistive at resonance, and it grows large as you move away from that frequency, approaching infinity in the ideal case as ω → 0 or ω → ∞.

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