Define the RC time constant and explain its role in charging a capacitor through a resistor.

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Multiple Choice

Define the RC time constant and explain its role in charging a capacitor through a resistor.

Explanation:
The essential idea is that the RC time constant sets how fast a capacitor charges through a resistor. In a charging scenario, the capacitor voltage climbs gradually toward the supply voltage, following an exponential approach. The time constant is the product of the resistance and the capacitance, τ = R · C, and it defines the pace of that charging. The voltage across the capacitor is Vc(t) = V_final [1 − e^(−t/τ)], assuming the capacitor starts discharged and the final voltage is the supply. This means after one time constant, the capacitor reaches about 63% of the final voltage; after five time constants, it’s over 99%. The correct statement uses τ = RC and the proper charging form; the other forms either misstate τ, apply the wrong exponential behavior, or describe discharging rather than charging.

The essential idea is that the RC time constant sets how fast a capacitor charges through a resistor. In a charging scenario, the capacitor voltage climbs gradually toward the supply voltage, following an exponential approach. The time constant is the product of the resistance and the capacitance, τ = R · C, and it defines the pace of that charging. The voltage across the capacitor is Vc(t) = V_final [1 − e^(−t/τ)], assuming the capacitor starts discharged and the final voltage is the supply. This means after one time constant, the capacitor reaches about 63% of the final voltage; after five time constants, it’s over 99%. The correct statement uses τ = RC and the proper charging form; the other forms either misstate τ, apply the wrong exponential behavior, or describe discharging rather than charging.

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